OSSC Combined Technical Service Exam Recruitment 2022 | Check Eligibility For 1225 Group B Posts @ www.ossc.gov.in: OSSC CTS Recruitment 2022 was released by the higher officials of OSSC at the official site i.e www.ossc.gov.in to fill the 1225 vacancies. From 11th November 2022 onwards officials activate the OSSC CTS Application Form 2022 link. So candidates apply for this OSSC Combined Technical Service Exam Recruitment 2022 through this site.
11 ନଭେମ୍ବର 2022 ପରଠାରୁ, OSSC CTS ଆବେଦନ ଫର୍ମ 2022 ଏହାର ଅଫିସିଆଲ୍ ୱେବସାଇଟ୍ www.ossc.gov.in ରେ ଉପଲବ୍ଧ ହେବ, 1225 ଟି ପଦବୀ ପୂରଣ କରିବାକୁ |
However, OSSC CTS Vacancy 2022 links will deactivate on 10th December 2022. So before that date interested and eligible candidates can apply for it. But it is very recommended to read the complete OSSC CTS Notification 2022 to know the eligibility criteria. Fortunately in this article, we clearly explained the eligibility criteria of OSSC JE Recruitment 2022 so read it for your understanding purpose.
Info of OSSC CTS Recruitment 2022
organization Name | Odisha Staff Selection Commission (OSSC) |
Name of Post |
|
Name of Exam | OSSC Combined Technical Service Exam |
Number of Vacancies | 1225 Vacancies |
Category | Odisha Govt Jobs |
Application Starting Date | 11th November 2022 |
Application Closing Date | 10th December 2022 |
Location | Odisha |
Minimum Location | Diploma |
Official Website | www.ossc.gov.in |
OSSC Combined Technical Service Exam Recruitment 2022
The OSSC Combined Technical Service Exam Recruitment 2022 is a very good opportunity for unemployed candidates who are living in the Odisha region. So eligible candidates can use this opportunity to apply for 1225 OSSC CTS Vacancy 2022. Applicants can use this article to fill out the OSSC CTS Application Form 2022. Because here we provided all the links to easily apply for the OSSC JE Recruitment 2022.
In the below sections of this page, you can see the eligibility create which explains the OSSC CTS Notification 2022. So candidates read the entire eligibility criteria and apply for it from 11th November 2022. Below we mentioned links will active until 10th December 2022 after that the links will not work for applying for OSSC CTS Recruitment 2022.
Eligibility Criteria
Educational Qualification
The candidates who want to apply for the OSSC CTS Recruitment 2022 must have the following educational qualifications.
- Junior Engineer: Applicant must possess a Diploma in a relevant engineering discipline.
- Assistant Training Officer(ATO): The candidate should have a Diploma/ Degree from any AICTE-recognized institute or NCVT-recognized institute with NAC/NTC.
Age Limit
Applicants who have the following age limit are eligible for this OSSC Combined Technical Service Exam Recruitment 2022.
- Minimum Age: 18 Years
- Maximum Age: 38 Years
- Age Relaxation is applicable as per the norms.
Application Fee
- Candidates have to check the official OSSC CTS Notification 2022 for the application form.
Selection Process
Candidates can select for this OSSC CTS Recruitment 2022 based on the following selection process.
- Prelims Exam
- Mains Exam
- Certificate Verification
Salary
The candidates who are selected for this OSSC JE Recruitment 2022 can get the following amount of salary.
- Salary: Rs. 35400-112400/-
Vacancy
The total of OSSC CTS Vacancy 2022 is 1225 and below the tabular form, we mentioned vacancy details clearly.
Name of Post | Number of Vacancies |
Junior Engineer Civil | 1008 |
Assistant Training Officer | 217 |
Total | 1225 Vacancies |
Fill Out the OSSC CTS Application Form 2022 @ www.ossc.gov.in
- Go to the official site i.e www.ossc.gov.in
- Now you can see what’s new section.
- Under that section, you can see the OSSC CTS Notification 2022.
- Tap on it and read it carefully.
- If you feel you are eligible then click on the application which is available on the home page.
- By entering your details you can submit your OSSC CTS Application Form 2022.
Important Links | |
OSSC CTS Notification 2022 | Click Here |
OSSC CTS Application Form | Click Here (Link Will Be activated from 11th November 2022) |